X^2+2x=288

Solution for X^2+2x=288 equation:

X^2+2X=288

We move all terms to the left:

X^2+2X-(288)=0

a = 1; b = 2; c = -288;
Δ = b2-4ac
Δ = 22-4·1·(-288)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-34}{2*1}=\frac{-36}{2}
=-18
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+34}{2*1}=\frac{32}{2}
=16
$